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	Comments on: NCTM 2010 â€” Day Three	</title>
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	<description>less helpful</description>
	<lastBuildDate>Mon, 29 Nov 2010 13:50:54 +0000</lastBuildDate>
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		<title>
		By: dy/dan &#187; Blog Archive &#187; An Open Video Message To Steve Leinwand And Jerry Becker		</title>
		<link>/2010/nctm-2010-%e2%80%94-day-three/#comment-270960</link>

		<dc:creator><![CDATA[dy/dan &#187; Blog Archive &#187; An Open Video Message To Steve Leinwand And Jerry Becker]]></dc:creator>
		<pubDate>Mon, 29 Nov 2010 13:50:54 +0000</pubDate>
		<guid isPermaLink="false">/?p=6755#comment-270960</guid>

					<description><![CDATA[[...] the third day at NCTM I wrote: It struck me several times throughout both conferences that we need to counter-program a [...]]]></description>
			<content:encoded><![CDATA[<p>[&#8230;] the third day at NCTM I wrote: It struck me several times throughout both conferences that we need to counter-program a [&#8230;]</p>
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		<title>
		By: Eileen		</title>
		<link>/2010/nctm-2010-%e2%80%94-day-three/#comment-260438</link>

		<dc:creator><![CDATA[Eileen]]></dc:creator>
		<pubDate>Mon, 17 May 2010 18:06:42 +0000</pubDate>
		<guid isPermaLink="false">/?p=6755#comment-260438</guid>

					<description><![CDATA[I love these!  I have a bunch of this type of stuff I have collected over the years, some of it ancient, for ways to include practice without sacrificing higher-level thinking.  The kids love it too and they start to see math as the fun game that it is.  I think half my job as a middle school teacher is to help kids have good feelings about math so that they actually desire to continue on with it.  And that doesn&#039;t mean I have to sacrifice rigor or learning to do so.]]></description>
			<content:encoded><![CDATA[<p>I love these!  I have a bunch of this type of stuff I have collected over the years, some of it ancient, for ways to include practice without sacrificing higher-level thinking.  The kids love it too and they start to see math as the fun game that it is.  I think half my job as a middle school teacher is to help kids have good feelings about math so that they actually desire to continue on with it.  And that doesn&#8217;t mean I have to sacrifice rigor or learning to do so.</p>
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		<title>
		By: Dan Meyer		</title>
		<link>/2010/nctm-2010-%e2%80%94-day-three/#comment-260333</link>

		<dc:creator><![CDATA[Dan Meyer]]></dc:creator>
		<pubDate>Sat, 15 May 2010 03:32:25 +0000</pubDate>
		<guid isPermaLink="false">/?p=6755#comment-260333</guid>

					<description><![CDATA[Got that fixed now. Thanks for the edit.]]></description>
			<content:encoded><![CDATA[<p>Got that fixed now. Thanks for the edit.</p>
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		<title>
		By: David		</title>
		<link>/2010/nctm-2010-%e2%80%94-day-three/#comment-260315</link>

		<dc:creator><![CDATA[David]]></dc:creator>
		<pubDate>Fri, 14 May 2010 19:59:11 +0000</pubDate>
		<guid isPermaLink="false">/?p=6755#comment-260315</guid>

					<description><![CDATA[vlk: It&#039;s a typo. The number in the middle rectangle is the sum of the numbers in the adjacent circles, not the difference.]]></description>
			<content:encoded><![CDATA[<p>vlk: It&#8217;s a typo. The number in the middle rectangle is the sum of the numbers in the adjacent circles, not the difference.</p>
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		<title>
		By: vlk		</title>
		<link>/2010/nctm-2010-%e2%80%94-day-three/#comment-260301</link>

		<dc:creator><![CDATA[vlk]]></dc:creator>
		<pubDate>Fri, 14 May 2010 14:38:46 +0000</pubDate>
		<guid isPermaLink="false">/?p=6755#comment-260301</guid>

					<description><![CDATA[Sorry, I don&#039;t get the illustrated arithmogon.  If I understand the rules correctly, there is no solution to it.  If the vertices are A,B, and C, it results in 3 equations,
A-B=7
B-C=9
C-A=8

So C=A+8,
hence B-C=B-A-8=9 ==&#062; B-A=17, but B-A is already stated to be -7.]]></description>
			<content:encoded><![CDATA[<p>Sorry, I don&#8217;t get the illustrated arithmogon.  If I understand the rules correctly, there is no solution to it.  If the vertices are A,B, and C, it results in 3 equations,<br />
A-B=7<br />
B-C=9<br />
C-A=8</p>
<p>So C=A+8,<br />
hence B-C=B-A-8=9 ==&gt; B-A=17, but B-A is already stated to be -7.</p>
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		<title>
		By: David Radcliffe		</title>
		<link>/2010/nctm-2010-%e2%80%94-day-three/#comment-259969</link>

		<dc:creator><![CDATA[David Radcliffe]]></dc:creator>
		<pubDate>Wed, 05 May 2010 20:32:22 +0000</pubDate>
		<guid isPermaLink="false">/?p=6755#comment-259969</guid>

					<description><![CDATA[Thanks, this is great stuff! I have saved Becker&#039;s handout for future reference. By the way, the arithmogon problem has an interesting geometric interpretation via inscribed circles. I created a GeoGebra worksheet to demonstrate this at http://cmath.org/incircle.html.]]></description>
			<content:encoded><![CDATA[<p>Thanks, this is great stuff! I have saved Becker&#8217;s handout for future reference. By the way, the arithmogon problem has an interesting geometric interpretation via inscribed circles. I created a GeoGebra worksheet to demonstrate this at <a href="http://cmath.org/incircle.html" rel="nofollow ugc">http://cmath.org/incircle.html</a>.</p>
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